If it's not what You are looking for type in the equation solver your own equation and let us solve it.
D( x )
x = 0
x^2 = 0
x = 0
x = 0
x^2 = 0
x^2 = 0
1*x^2 = 0 // : 1
x^2 = 0
x = 0
x in (-oo:0) U (0:+oo)
7-(1/x)-(9/(x^2)) = 0
7-x^-1-9*x^-2 = 0
t_1 = x^-1
7-9*t_1^2-1*t_1^1 = 0
7-9*t_1^2-t_1 = 0
DELTA = (-1)^2-(-9*4*7)
DELTA = 253
DELTA > 0
t_1 = (253^(1/2)+1)/(-9*2) or t_1 = (1-253^(1/2))/(-9*2)
t_1 = (253^(1/2)+1)/(-18) or t_1 = (1-253^(1/2))/(-18)
t_1 = (253^(1/2)+1)/(-18)
x^-1-((253^(1/2)+1)/(-18)) = 0
1*x^-1 = (253^(1/2)+1)/(-18) // : 1
x^-1 = (253^(1/2)+1)/(-18)
-1 < 0
1/(x^1) = (253^(1/2)+1)/(-18) // * x^1
1 = ((253^(1/2)+1)/(-18))*x^1 // : (253^(1/2)+1)/(-18)
-18*(253^(1/2)+1)^-1 = x^1
x = -18*(253^(1/2)+1)^-1
t_1 = (1-253^(1/2))/(-18)
x^-1-((1-253^(1/2))/(-18)) = 0
1*x^-1 = (1-253^(1/2))/(-18) // : 1
x^-1 = (1-253^(1/2))/(-18)
-1 < 0
1/(x^1) = (1-253^(1/2))/(-18) // * x^1
1 = ((1-253^(1/2))/(-18))*x^1 // : (1-253^(1/2))/(-18)
-18*(1-253^(1/2))^-1 = x^1
x = -18*(1-253^(1/2))^-1
x in { -18*(253^(1/2)+1)^-1, -18*(1-253^(1/2))^-1 }
| (3y-5)/6=(2y-1)/3 | | Tan(4•3.14/3) | | 1-3(1-x)=4(x-1)+3 | | x+1=3+2(x+1) | | z^4-6z+4=0 | | -9(b-2)+2(b-13)=9+2(-b+9) | | 103-(6x+16)=6(x+8)+x | | x-(2-x)=12 | | p^2+10p-7=4 | | 2x-(2-x)=24 | | 3(x+2)-5(2x+7)=11x-3 | | 4*-3-2-2*-3=-3-5 | | 34-n=26 | | N-0.58=0.41 | | 3x*6y=360 | | (0.15)X+(0.10)8-(0.2)X=5 | | 4=-10(8+4x)+4(3x+2) | | (2y-3)(1-y)=0 | | P=1,200/0.02*4 | | 8(y+2)-10y=2y+8 | | 2(3)+2= | | 125-(7x+7)=7(x+4)+x | | 40x+10y=43000 | | f(31)=0.41ln(31+1) | | 58N-0.58=0.41 | | 60+n=80 | | -19x-9y=-65 | | N-0.5=0.4 | | N+27=101 | | 7x+12y=125 | | b-1=4(b-2)-(b+3) | | -2(3x-5)=4x-2+4x |